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there are 17 blue marbles, 11 red marbles, 14 green marbles, and 7 yell…

Question

there are 17 blue marbles, 11 red marbles, 14 green marbles, and 7 yellow marble in a bag. what is the probability that if you select one marble at random, it will be yellow or green?
a 52%
b 46.1%
c 42.9%
d 14.3%

Explanation:

Step1: Calculate total number of marbles

We sum up the number of blue, red, green, and yellow marbles. So, \(17 + 11 + 14 + 7 = 49\) marbles in total.

Step2: Calculate number of yellow or green marbles

We add the number of yellow and green marbles. So, \(14 + 7 = 21\) marbles that are yellow or green.

Step3: Calculate the probability

Probability is the number of favorable outcomes (yellow or green marbles) divided by the total number of outcomes (total marbles). So, the probability \(P=\frac{21}{49}\approx0.4286\), which is approximately \(42.9\%\) when converted to a percentage.

Answer:

C. 42.9%