Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

test the claim about the difference between two population means \\( \\…

Question

test the claim about the difference between two population means \\( \mu _ { 1 } \\) and \\( \mu _ { 2 } \\) at the level of significance \\( \alpha \\). assume the samples are random and independent, and the populations are normally distributed.

claim: \\( \mu _ { 1 } = \mu _ { 2 } ; \alpha = 0.10 \\). assume \\( \sigma _ { 1 } ^ { 2 } = \sigma _ { 2 } ^ { 2 } \\)
sample statistics: \\( \overline { x } _ { 1 } = 35.8, s _ { 1 } = 3.6, n _ { 1 } = 12 \\) and
\\( \overline { x } _ { 2 } = 37.8, s _ { 2 } = 2.4, n _ { 2 } = 16 \\)

identify the null and alternative hypotheses. choose the correct answer below.

a. \\( h _ { 0 } : \mu _ { 1 } = \mu _ { 2 } \\)
\\( h _ { a } : \mu _ { 1 } \
eq \mu _ { 2 } \\)
b. \\( h _ { 0 } : \mu _ { 1 } \geq \mu _ { 2 } \\)
\\( h _ { a } : \mu _ { 1 } < \mu _ { 2 } \\)
c. \\( h _ { 0 } : \mu _ { 1 } > \mu _ { 2 } \\)
\\( h _ { a } : \mu _ { 1 } \leq \mu _ { 2 } \\)
d. \\( h _ { 0 } : \mu _ { 1 } < \mu _ { 2 } \\)
\\( h _ { a } : \mu _ { 1 } \geq \mu _ { 2 } \\)
e. \\( h _ { 0 } : \mu _ { 1 } \leq \mu _ { 2 } \\)
\\( h _ { a } : \mu _ { 1 } > \mu _ { 2 } \\)
f. \\( h _ { 0 } : \mu _ { 1 } \
eq \mu _ { 2 } \\)
\\( h _ { a } : \mu _ { 1 } = \mu _ { 2 } \\)

find the standardized test statistic t.
\\( t = - 1.76 \\)
(round to two decimal places as needed)

find the p - value.
\\( p = \\)
(round to three decimal places as needed.)

Explanation:

Step1: Determine the degrees of freedom

The formula for degrees of freedom when \(\sigma_1^{2}=\sigma_2^{2}\) is \(df=n_1 + n_2-2\).
Substitute \(n_1 = 12\) and \(n_2=16\) into the formula:
\(df=12 + 16-2=26\)

Step2: Calculate the P - value

Since the test is two - tailed (\(H_a:\mu_1
eq\mu_2\)) and \(t=-1.76\), we use the t - distribution table or a calculator.
Using a calculator (e.g., in R: \(2*pt(-1.76,26)\)), we find the P - value.
\(P = 2\times P(t_{26}\lt - 1.76)\)
\(P\approx0.090\)

Answer:

\(P = 0.090\)