Question

1. taylor and anne are building sand castles on the beach. taylors sand castle is \\(\frac{7}{8}\\) of a foot long. annes sand castle is \\(\frac{5}{8}\\) of a foot long. how much taller is taylors sand castle than annes?

Explanation:

Identify the given values

The length of Taylor's sand castle is:

$$ T = \frac{7}{8}\text{ foot} $$

The length of Anne's sand castle is:

$$ A = \frac{5}{8}\text{ foot} $$

Set up the subtraction

To find how much longer Taylor's castle is, subtract Anne's length from Taylor's length:

$$ \text{Difference} = T - A = \frac{7}{8} - \frac{5}{8} $$

Subtract the fractions

Since the denominators are already the same, subtract the numerators:

$$ \frac{7}{8} - \frac{5}{8} = \frac{7 - 5}{8} = \frac{2}{8} $$

Simplify the fraction

Divide the numerator and denominator by their greatest common divisor, which is 2:

$$ \frac{2 \div 2}{8 \div 2} = \frac{1}{4} $$

Answer:

\(\frac{1}{4}\) foot