Question

the table shows the linear relationship between the distance in feet below sea level and the time in seconds traveled by a submarine. submarine time (seconds) distance below sea level (feet) 0 460 18 604 34 732 52 876 70 1,020 what is the rate of change of the distance in feet below sea level with respect to time that the submarine traveled?

Explanation:

Step1: Recall rate - of - change formula

The rate of change (slope) formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $m=\frac{y_2 - y_1}{x_2 - x_1}$. Here, time is $x$ and distance below sea - level is $y$.

Step2: Choose two points

Let's choose the points $(0,460)$ and $(18,604)$.

Step3: Calculate the rate of change

$m=\frac{604 - 460}{18-0}=\frac{144}{18}=8$.

Answer:

8