Question

the table shows the coordinates of the vertices of △jkl and its image.
△jkl\t△jkl
j(-3, 0)\tj(-3, -4)
k(0, 4)\tk(0, 0)
l(2, 3)\tl(2, -1)
which translation maps △jkl onto its image?
4 units down
4 units up
4 units to the right
4 units to the left

Explanation:

To determine the translation, we analyze the coordinates of the vertices of $\triangle JKL$ and its image $\triangle J'K'L'$. For point $J(-3, 0)$ and $J'(-3, -4)$, the x - coordinate remains the same, and the y - coordinate changes from 0 to - 4, which is a decrease of 4. For $K(0, 4)$ and $K'(0, 0)$, the x - coordinate is unchanged, and the y - coordinate decreases by 4 (from 4 to 0). For $L(2, 3)$ and $L'(2, -1)$, the x - coordinate is the same, and the y - coordinate decreases by 4 (from 3 to - 1). Since the x - coordinates of all corresponding points are the same and the y - coordinates decrease by 4, the translation is 4 units down.

Answer:

A. 4 units down