QUESTION IMAGE
Question
a survey asked 40 students if they play an instrument and if they are in band.
- 25 students play an instrument.
- 20 students are in band.
- 20 students are not in band.
which table shows these data correctly entered in a two - way frequency table?
a.
| band | not in band | total | |
|---|---|---|---|
| dont play instrument | 0 | 15 | 15 |
| total | 20 | 20 | 40 |
b.
| band and play instrument | not in band and play instrument | total | |
|---|---|---|---|
| band and dont play instrument | 5 | 15 | 20 |
| total | 25 | 15 | 40 |
c.
| band | dont play instrument | total | |
|---|---|---|---|
| play instrument | 0 | 15 | 15 |
| total | 20 | 20 | 40 |
d.
| band | not in band | total | |
|---|---|---|---|
| dont play instrument | 5 | 15 | 20 |
| total | 25 | 15 | 40 |
Step1: Analyze total students
Total students are 40. For band: 20, not in band: 20. For play instrument: 25, don't play: \(40 - 25 = 15\).
Step2: Check each table
- Option A:
- Play instrument: Band = 20, Not in band = 5 (20 + 5 = 25, correct).
- Don't play instrument: Band = 0, Not in band = 15 (0 + 15 = 15, correct).
- Total Band: 20 + 0 = 20, Total Not in band: 5 + 15 = 20, Total students: 25 + 15 = 40. All totals match.
- Option B: Columns and rows are mislabeled (e.g., "Band and play instrument" as a column is incorrect for two - way table structure), so eliminate.
- Option C: Rows and columns are mislabeled (e.g., "Don't play instrument" as a column and "Not in band" as a row mix up categories), eliminate.
- Option D: Play instrument total is 20 (should be 25), Don't play instrument total is 20 (should be 15), Band total is 25 (should be 20), so incorrect.
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A.
| Band | Not in band | Total | |
|---|---|---|---|
| Don't play instrument | 0 | 15 | 15 |
| Total | 20 | 20 | 40 |