Question

1. in a survey of 850 students in a school, 90% reported having pets at home. if the margin of error is ±3.4%, what is the interval that is likely to contain the exact percent of all people who have pets at home? (4 points)

Explanation:

Step1: Identify the sample - proportion and margin of error

The sample - proportion $p = 90\%=0.9$ and the margin of error $E = 3.4\% = 0.034$.

Step2: Calculate the lower bound of the confidence interval

The lower bound is $p - E$. So, $0.9-0.034 = 0.866$ or $86.6\%$.

Step3: Calculate the upper bound of the confidence interval

The upper bound is $p + E$. So, $0.9 + 0.034=0.934$ or $93.4\%$.

Answer:

The interval is $86.6\%$ to $93.4\%$.