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surface area of solids using nets using the net of each solid shape, fi…

Question

surface area of solids using nets
using the net of each solid shape, find its surface area.
(first problem with triangular prism net and related areas: area of j =
area of k =
area of l =
area of m =
area of n =
surface area =
21 (second problem with pyramid net and related areas: area of u =
area of v =
area of w =
area of x =
area of y =
surface area =

  1. (third problem with rectangular prism net and related areas: area of a =

area of b =
area of c =
area of d =
area of e =
surface area = )

Explanation:

Step1: Analyze the first solid (triangular prism)

The triangular base has legs 6 ft, 8 ft, hypotenuse 10 ft (by Pythagoras: \(6^2 + 8^2 = 10^2\)). The height of the prism is 10 ft.

  • Area of \(J\) (triangle): \(\frac{1}{2} \times 6 \times 8 = 24\) sq ft.
  • Area of \(K\) (rectangle): \(8 \times 10 = 80\) sq ft.
  • Area of \(L\) (rectangle): \(6 \times 10 = 60\) sq ft.
  • Area of \(M\) (rectangle): \(10 \times 10 = 100\) sq ft.
  • Area of \(N\) (triangle): same as \(J\), \(24\) sq ft.

Step2: Calculate surface area

Sum all areas: \(24 + 80 + 60 + 100 + 24 = 288\) sq ft.

Step1: Analyze the second solid (square pyramid)

Base is square with side 16 yd. Slant height (height of triangular face) is 15 yd.

  • Area of \(U, V, W, X, Y\): \(U, V, X, Y\) are triangles, \(W\) is square.
  • Area of \(W\) (square): \(16 \times 16 = 256\) sq yd.
  • Area of one triangular face (e.g., \(U\)): \(\frac{1}{2} \times 16 \times 15 = 120\) sq yd. There are 4 triangular faces (\(U, V, X, Y\)).

Step2: Calculate surface area

Sum: \(256 + 4 \times 120 = 256 + 480 = 736\) sq yd.

Step1: Analyze the third solid (rectangular prism)

Dimensions: Let's assume length \(l = 10\) in, width \(w = 5\) in, height \(h = 12\) in (from the net).

  • Area of each pair of faces:
  • \(A, F\): \(5 \times 10 = 50\) each.
  • \(B, E\): \(10 \times 12 = 120\) each.
  • \(C, D\): \(5 \times 12 = 60\) each.

Step2: Calculate surface area

Sum: \(2(50 + 120 + 60) = 2 \times 230 = 460\) sq in.

Answer:

  1. Surface Area of triangular prism: \(\boldsymbol{288}\) sq ft.
  2. Surface Area of square pyramid: \(\boldsymbol{736}\) sq yd.
  3. Surface Area of rectangular prism: \(\boldsymbol{460}\) sq in. (Note: Dimensions assumed from net; adjust if actual dimensions differ.)