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Question
suppose you are conducting a survey to estimate the proportion of employees in a particular industry in your city who earn above the median monthly income. you sample 300 employees from various companies within the industry and find that 180 of them earn above the median monthly income. assuming the sample is representative of the population, what is your best estimate of the proportion of employees in this industry who earn above the median monthly income?
0.50
0.60
0.40
0.70
Identify the given values
$$
LATEXBLOCK0
$$
Calculate the sample proportion
$$
\hat{p} = \frac{x}{n} = \frac{180}{300} = 0.60
$$
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- (A) 0.50
- (B) 0.60 (Correct answer)
- (C) 0.40
- (D) 0.70