Question

suppose 220 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. use a 0.10 significance level to test the claim that more than 20% of users develop nausea. identify the null and alternative hypotheses for this test. choose the correct answer below. a. $h_0: p = 0.20$, $h_1: p
eq 0.20$ b. $h_0: p > 0.20$, $h_1: p = 0.20$ c. $h_0: p = 0.20$, $h_1: p > 0.20$ d. $h_0: p = 0.20$, $h_1: p < 0.20$ identify the test statistic for this hypothesis test. the test statistic for this hypothesis test is (round to two decimal places as needed.)

Explanation:

Step1: Calculate the sample proportion

The sample proportion $\hat{p}=\frac{x}{n}$, where $x = 54$ (number of successes) and $n=220$ (sample size).
$\hat{p}=\frac{54}{220}\approx0.2455$

Step2: Calculate the test - statistic

The formula for the test - statistic $z$ in a one - sample proportion test is $z=\frac{\hat{p}-p}{\sqrt{\frac{p(1 - p)}{n}}}$, where $p = 0.20$ (the proportion in the null hypothesis).
Substitute the values:

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Answer:

The test statistic for this hypothesis test is $1.69$