Question

a summer camp builds 4 new obstacle courses. for the first week, the camp director records the number of campers who successfully complete each course.
course a 58 succeed out of 100
course b 17 succeed out of 25
course c 31 succeed out of 50
course d 79 succeed out of 100
order the obstacle courses from the least percent of successful campers to the greatest percent of successful campers.

Explanation:

Step1: Calculate the percentage for Course B

To find the percentage, use the formula \(\frac{\text{number of successes}}{\text{total number}}\times100\). For Course B, \(\frac{17}{25}\times100=\frac{17\times100}{25}= 68\%\)

Step2: Calculate the percentage for Course C

For Course C, \(\frac{31}{50}\times100=\frac{31\times100}{50}=62\%\)

Step3: List all percentages

Course A: \(58\%\), Course B: \(68\%\), Course C: \(62\%\), Course D: \(79\%\)

Answer:

Course A, Course C, Course B, Course D