Question

subtract
$(9y^2 + 9y - 9) - (-6y + 8)$

$(9y^2 + 9y - 9) - (-6y + 8) = \square$ (simplify your answer)

Explanation:

Step1: Distribute the negative sign

To subtract \((-6y + 8)\) from \((9y^2 + 9y - 9)\), we distribute the negative sign to each term in the second polynomial:
\((9y^2 + 9y - 9) + 6y - 8\)

Step2: Combine like terms

Now, we combine the like terms. The \(y^2\) term remains as is, we combine the \(y\) terms (\(9y + 6y\)) and the constant terms (\(-9 - 8\)):

• For the \(y^2\) term: \(9y^2\)
• For the \(y\) terms: \(9y + 6y = 15y\)
• For the constant terms: \(-9 - 8 = -17\)

Putting it all together, we get \(9y^2 + 15y - 17\).

Answer:

\(9y^2 + 15y - 17\)