Question

students in a jewelry - making club store their beads in 2 containers. each container has 100 beads of different colors. the box plots show the number of yellow beads found in random samples of 50 beads from each container.
based on the data sets, can the students expect more yellow beads in container a or container b? about how many more?
the students can expect that container has about more yellow beads.

Explanation:

Step1: Identify medians from box plots

The median (middle line of box plot) for Container A is around 15, for Container B around 33.

Step2: Calculate difference in medians

Difference = Median of B - Median of A = $33 - 15 = 18$

Step3: Scale to full container

Each container has 100 beads (2x sample size 50). So total expected difference = $18 \times 2 = 36$? No, wait—wait, the question asks about per container? Wait no, the box plot shows per sample (50 beads). Wait the first blank: Container B (since its median is higher). The second blank: the difference per sample is ~18, but wait the container has 100 beads, so if per 50 beads B has ~18 more, then per 100 beads it's ~36? Wait no, the question says "how many more yellow beads" in the container. Since each container is 100 beads, and the sample is 50 beads: if sample of 50 from B has ~18 more than A, then 100 beads would be ~36 more. But wait the box plot: Container A's median is ~15, Container B's ~33. Difference per sample: 18. So per container (100 beads): 18*2=36.

Answer:

B, 36