Question

station 4:

1. ( x + 4y = 2 )

( 3y + x = 10 )

Explanation:

Step1: Identify the system of equations

We have the system:

$$\begin{cases} x + 4y = 2 \\ x + 3y = 10 \end{cases}$$

(Assuming the first equation is \(x + 4y = 2\) and the second is \(x + 3y = 10\) from the hand - written text)

Step2: Subtract the second equation from the first

\((x + 4y)-(x + 3y)=2 - 10\)
Simplify the left - hand side: \(x+4y - x - 3y=y\)
Simplify the right - hand side: \(2-10=-8\)
So, \(y=-8\)

Step3: Substitute \(y = - 8\) into the first equation

Substitute \(y=-8\) into \(x + 4y = 2\):
\(x+4\times(-8)=2\)
\(x-32 = 2\)
Add 32 to both sides: \(x=2 + 32=34\)

Answer:

\(x = 34,y=-8\)