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Question
spiral 3 lesson 5 - simple trinomial factoring - special cases
factor each completely.
- $6x^{2}+12x - 378$ \t\t\t\t\t2) $2b^{2}-38b + 180$
- $2x^{2}-14x + 12$ \t\t\t\t\t4) $2a^{2}-14a + 20$
- $6x^{2}-42x - 48$ \t\t\t\t\t6) $-6a^{2}-30a - 24$
- $-6n^{2}-36n$ \t\t\t\t\t\t8) $2r^{2}-32r + 120$
- $5n^{2}-15n - 140$ \t\t\t\t\t10) $-4x^{2}-8x$
Let's solve each problem one by one using factoring techniques (greatest common factor, then factoring the quadratic):
1) \( 6x^2 + 12x - 378 \)
Step 1: Factor out GCF (6)
\( 6(x^2 + 2x - 63) \)
Step 2: Factor the quadratic \( x^2 + 2x - 63 \)
Find two numbers that multiply to -63 and add to 2: 9 and -7.
\( x^2 + 2x - 63 = (x + 9)(x - 7) \)
Step 3: Combine
\( 6(x + 9)(x - 7) \)
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\( 6(x + 9)(x - 7) \)
2) \( 2b^2 - 38b + 180 \)
Step 1: Factor out GCF (2)
\( 2(b^2 - 19b + 90) \)
Step 2: Factor the quadratic \( b^2 - 19b + 90 \)
Find two numbers that multiply to 90 and add to -19: -9 and -10.
\( b^2 - 19b + 90 = (b - 9)(b - 10) \)
Step 3: Combine
\( 2(b - 9)(b - 10) \)