QUESTION IMAGE
Question
solving multi-step equations
directions : show all work on a separate piece of paper.
circle the answer choice that represents the correct answer.
then use the color choice to color the picture.
| question | choice a | choice b | choice c | |
|---|---|---|---|---|
| 2 | $-5x + 5x + 2x - 6x - 12x = -16$ | $x = 1$ green | $x = -1$ orange | $x = 16$ blue |
| 3 | $3(x - 6) = 6$ | $x = 4$ black | $x = -4$ pink | $x = 8$ yellow |
| 4 | $-9 - x - 7x = 7 - 10x$ | $x = -8$ blue | $x = 8$ purple | $x = 18$ red |
| 5 | $10 + 4x = 6x - 10$ | $x = 10$ blue | $x = -10$ black | $x = -2$ green |
| 6 | $7x = 8x - 3$ | $x = 5$ pink | $x = 3$ orange | $x = -3$ black |
| 7 | $-6x - 10 = 10 - 10x$ | $x = -5$ gray | $x = 5$ pink | $x = 10$ black |
| 8 | $-8x = -7x + 10$ | $x = -10$ green | $x = 10$ blue | $x = 25$ orange |
| 9 | $-2x + 6 = -x$ | $x = -6$ blue | $x = -8$ black | $x = 6$ yellow |
| 10 | $2(x + 8) + -8 = -6$ | $x = 7$ white | $x = -7$ pink | $x = 17$ purple |
| 11 | $3x + 30 = 14x + 140$ | $x = 5$ orange | $x = 20$ red | $x = -10$ blue |
| 12 | $65x - 50 = 40x + 150$ | $x = 40$ yellow | $x = 5$ pink | $x = 8$ purple |
Step1: Solve the equation \(5x - 4x = 15\)
Simplify the left side: \(5x - 4x = x\), so the equation becomes \(x = 15\).
Step2: Solve the equation \(-5x + 5x + 2x - 6x - 12x = -16\)
Combine like terms: \((-5x + 5x)+(2x - 6x - 12x)=0+( - 16x)= - 16x\), so \(-16x=-16\), divide both sides by -16: \(x = 1\).
Step3: Solve the equation \(3(x - 6)=6\)
Distribute the 3: \(3x-18 = 6\), add 18 to both sides: \(3x=6 + 18=24\), divide by 3: \(x = 8\).
Step4: Solve the equation \(-9 - x - 7x = 7 - 10x\)
Combine like terms on left: \(-9-8x = 7 - 10x\), add \(10x\) to both sides: \(-9 + 2x=7\), add 9 to both sides: \(2x=16\), divide by 2: \(x = 8\)? Wait, no, let's re - do: \(-9-8x=7 - 10x\), add \(10x\) to both sides: \(-9 + 2x=7\), add 9: \(2x=16\), \(x = 8\)? But the option A is \(x=-8\), maybe I made a mistake. Wait, original equation: \(-9 - x - 7x=7 - 10x\), left side: \(-9-8x\), right side: \(7 - 10x\). Add \(10x\) to both sides: \(-9 + 2x=7\), add 9: \(2x = 16\), \(x = 8\). But the option A is \(x=-8\), maybe the user's marked answer is wrong, but according to calculation, \(x = 8\). Wait, maybe I misread the equation. Let me check again: \(-9 - x - 7x=7 - 10x\), \(-9-8x=7 - 10x\), add \(10x\): \(-9 + 2x=7\), \(2x=16\), \(x = 8\). But the marked answer is A (\(x=-8\) BLUE). Maybe a typo, but following the calculation steps as per the problem's requirement to solve.
Step5: Solve the equation \(10 + 4x = 6x - 10\)
Subtract \(4x\) from both sides: \(10=2x - 10\), add 10: \(20 = 2x\), divide by 2: \(x = 10\).
Step6: Solve the equation \(7x = 8x - 3\)
Subtract \(7x\) from both sides: \(0=x - 3\), add 3: \(x = 3\)? Wait, \(7x=8x - 3\), subtract \(8x\): \(-x=-3\), so \(x = 3\).
Step7: Solve the equation \(-6x - 10 = 10 - 10x\)
Add \(10x\) to both sides: \(4x-10 = 10\), add 10: \(4x=20\), divide by 4: \(x = 5\).
Step8: Solve the equation \(-8x=-7x + 10\)
Add \(7x\) to both sides: \(-x = 10\), multiply by -1: \(x=-10\).
Step9: Solve the equation \(-2x + 6=-x\)
Add \(2x\) to both sides: \(6=x\), so \(x = 6\).
Step10: Solve the equation \(2(x + 8)-8=-6\)
Distribute: \(2x+16 - 8=-6\), simplify: \(2x + 8=-6\), subtract 8: \(2x=-14\), divide by 2: \(x=-7\).
Step11: Solve the equation \(3x + 30 = 14x + 140\)
Subtract \(3x\): \(30 = 11x+140\), subtract 140: \(-110 = 11x\), divide by 11: \(x=-10\).
Step12: Solve the equation \(65x - 50 = 40x + 150\)
Subtract \(40x\): \(25x-50 = 150\), add 50: \(25x=200\), divide by 25: \(x = 8\).
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- \(x = 15\) (Choice A)
- \(x = 1\) (Choice A)
- \(x = 8\) (Choice C)
- Let's re - solve: \(-9 - x - 7x=7 - 10x\)
\(-9-8x=7 - 10x\)
\(-8x + 10x=7 + 9\)
\(2x=16\)
\(x = 8\) (But marked as A, maybe error)
- \(x = 10\) (Choice A)
- \(7x=8x - 3\)
\(8x-7x = 3\)
\(x = 3\) (Choice B)
- \(x = 5\) (Choice B)
- \(x=-10\) (Choice A)
- \(x = 6\) (Choice C)
- \(x=-7\) (Choice B)
- \(x=-10\) (Choice C)
- \(x = 8\) (Choice C)
(Note: Some of the marked answers in the image may have calculation errors based on the standard solving of linear equations.)