Question

solve $x^2 = -18$, where $x$ is a real number. simplify your answer as much as possible. if there is more than one solution, separate them with commas. if there is no solution, click
o solution.\

Explanation:

Step1: Recall the property of real numbers' squares

For any real number \( x \), the square of \( x \), i.e., \( x^{2} \), is always non - negative. That is, \( x^{2}\geq0 \) for all real numbers \( x \).

Step2: Analyze the given equation

The given equation is \( x^{2}=- 18 \). But we know that \( - 18<0 \), and there is no real number whose square is a negative number.

Answer:

No solution