Question

solve $x^2 = 41$, where $x$ is a real number. simplify your answer as much as possible. if there is more than one solution, separate them with commas. if there is no solution, click
o solution.\ $x = \square$

Explanation:

Step1: Take square root of both sides

To solve the equation \( x^2 = 41 \) for \( x \), we take the square root of both sides. Remember that when we take the square root of a number, we get both a positive and a negative solution because \( (\sqrt{a})^2 = a \) and \( (-\sqrt{a})^2 = a \) for any non - negative real number \( a \). So, taking the square root of both sides of \( x^2=41 \), we have \( x=\pm\sqrt{41} \).

Answer:

\( \sqrt{41},-\sqrt{41} \)