QUESTION IMAGE
Question
solve for x. round to the nearest tenth, if necessary.
Step1: Identify the trigonometric ratio
In a right - triangle, \(\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}\). Here, \(\theta = 38^{\circ}\), the opposite side to \(\angle T\) is \(RS = 99\), and the hypotenuse is \(RT=x\). So, \(\sin(38^{\circ})=\frac{99}{x}\).
Step2: Solve for \(x\)
Rearrange the equation \(\sin(38^{\circ})=\frac{99}{x}\) to get \(x=\frac{99}{\sin(38^{\circ})}\).
We know that \(\sin(38^{\circ})\approx0.6157\). Then \(x=\frac{99}{0.6157}\approx160.8\).
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\(x\approx160.8\)