Question

solve for x. round to the nearest tenth of a degree, if necessary.

Explanation:

Step1: Aplicar el teorema de Pitágoras para encontrar el lado faltante

$$ RS=\sqrt{QS^{2}-QR^{2}}=\sqrt{71^{2}-64^{2}}=\sqrt{5041 - 4096}=\sqrt{945}\approx30.7 $$

Step2: Aplicar la función trigonométrica coseno

$$ \cos x=\frac{RS}{QS}=\frac{30.7}{71}\approx0.4324 $$

Step3: Encontrar el ángulo \(x\)

$$ x=\cos^{-1}(0.4324)\approx64.4^{\circ} $$

Answer:

\(x\approx64.4^{\circ}\)