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Question
i can solve real-world equations. 6.9a, 6.9c
- micah and his brother found some cash at a bus stop. they split the money evenly, each getting $16. how much money did they find?
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- a large box of cereal costs $3.50. how many boxes can you purchase with $28.00?
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- jada swam 200 meters more than molly. jada swam a total of 800 meters. how many meters did molly swim?
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- a recipe calls for 2.5 cups of sugar. you have already added 0.75 cups. how many more cups of sugar do you need to add?
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- jefferson high school has an enrollment of 1,864 students. in may, 564 students will graduate. how many students will be enrolled after graduation?
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- mrs. turner baked 120 cookies. she decided to give \\(\frac{1}{5}\\) of them to her students. how many cookies did she take to her students?
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Problem 14
Step1: Define total money as \( x \)
Split evenly: \( \frac{x}{2} = 16 \)
Step2: Solve for \( x \)
\( x = 16 \times 2 = 32 \)
Problem 15
Step1: Define boxes as \( n \)
Cost per box: \( 3.50n = 28.00 \)
Step2: Solve for \( n \)
\( n = \frac{28.00}{3.50} = 8 \)
Problem 16
Step1: Define Molly's meters as \( m \)
Jada's distance: \( m + 200 = 800 \)
Step2: Solve for \( m \)
\( m = 800 - 200 = 600 \)
Problem 17
Step1: Define needed cups as \( c \)
Total sugar: \( 0.75 + c = 2.5 \)
Step2: Solve for \( c \)
\( c = 2.5 - 0.75 = 1.75 \)
Problem 18
Step1: Define remaining students as \( s \)
Enrollment after graduation: \( 1864 - 564 = s \)
Step2: Calculate \( s \)
\( s = 1864 - 564 = 1300 \)
Problem 19
Step1: Define cookies given as \( k \)
Fraction of cookies: \( k = 120 \times \frac{1}{6} \)
Step2: Calculate \( k \)
\( k = 20 \)
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- Equation: \( \frac{x}{2}=16 \); Answer: 32
- Equation: \( 3.50n=28.00 \); Answer: 8
- Equation: \( m+200=800 \); Answer: 600
- Equation: \( 0.75+c=2.5 \); Answer: 1.75
- Equation: \( 1864-564=s \); Answer: 1300
- Equation: \( k=120\times\frac{1}{6} \); Answer: 20