QUESTION IMAGE
Question
8.6 solve radical equations (homework)
score: 12/16 answered: 12/16
question 13
solve.
\\(\sqrt3{5z - 3}+7 = 9\\)
\\(z =\\)
Step1: Isolate the cube - root term
Subtract 7 from both sides of the equation $\sqrt[3]{5z - 3}+7 = 9$.
$\sqrt[3]{5z - 3}=9 - 7$
$\sqrt[3]{5z - 3}=2$
Step2: Eliminate the cube - root
Cube both sides of the equation.
$(\sqrt[3]{5z - 3})^3=2^3$
$5z-3 = 8$
Step3: Solve for z
Add 3 to both sides: $5z=8 + 3$, so $5z=11$.
Then divide both sides by 5: $z=\frac{11}{5}=2.2$
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$z = 2.2$