Question

solve for x b = (mx^2 + y)/c

Explanation:

Step1: Isolate the term with $x$

First, subtract $y$ from both sides of the equation $b=\frac{mx^{2}}{c}+y$. We get $b - y=\frac{mx^{2}}{c}$.

Step2: Solve for $x^{2}$

Multiply both sides of the equation $b - y=\frac{mx^{2}}{c}$ by $c$ to get $c(b - y)=mx^{2}$. Then divide both sides by $m$ (assuming $m
eq0$), so $x^{2}=\frac{c(b - y)}{m}$.

Step3: Solve for $x$

Take the square - root of both sides. We have $x=\pm\sqrt{\frac{c(b - y)}{m}}$ (assuming $\frac{c(b - y)}{m}\geq0$).

Answer:

$x=\pm\sqrt{\frac{c(b - y)}{m}}$