solve for y. (just put the number, not y = !!!!!)
your answer

Question

Accepted Answer

# Explanation:
## Step1: Use properties of a rectangle
In a rectangle, opposite sides are equal. So, $AB = CD$ and $AD = BC$. First, use $AB = CD$ to find $x$.
$2y + 4=5x - 4$ (This equation is not directly used for $y$ yet). Use $AD = BC$. Since $AD=5y + 1$ and $BC = 3x$, we have $5y+1 = 3x$, so $x=\frac{5y + 1}{3}$.
## Step2: Substitute $x$ into $AB = CD$
Substitute $x=\frac{5y + 1}{3}$ into $2y+4 = 5x-4$.
$$
\begin{align*}
2y+4&=5\times\frac{5y + 1}{3}-4\
2y+4&=\frac{25y+5}{3}-4\
2y+4&=\frac{25y + 5-12}{3}\
2y+4&=\frac{25y-7}{3}\
3\times(2y + 4)&=25y-7\
6y+12&=25y-7\
12 + 7&=25y-6y\
19&=19y
\end{align*}
$$

# Answer:
$1$

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QUESTION IMAGE

Question

Explanation:

Step1: Use properties of a rectangle

Step2: Substitute \(x\) into \(AB = CD\)

Answer: