Question

solve the inequality and graph the solution. 3r + 9 ≥ 3 to draw a ray, plot an endpoint and select an arrow. select an endpoint to change it from closed to open. select the middle of the ray to delete it: -5 -4 -3 -2 -1 0 1 2 3 4 5

Explanation:

Step1: Subtract 9 from both sides

$$3r+9 - 9\geq3 - 9$$
$$3r\geq - 6$$

Step2: Divide both sides by 3

$$\frac{3r}{3}\geq\frac{-6}{3}$$
$$r\geq - 2$$

To graph \(r\geq - 2\):

• Plot a closed endpoint at \(r = - 2\) (because the inequality is \(\geq\), which includes the value \(-2\)).
• Draw an arrow to the right (since \(r\) is greater than or equal to \(-2\)).

Answer:

The solution of the inequality \(3r + 9\geq3\) is \(r\geq - 2\). On the number - line, there is a closed circle at \(-2\) and an arrow pointing to the right.