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Question
solve the inequality and graph the solution. -3b + 9 ≥ 3 plot the endpoints. select an endpoint to change it from closed to open. select the middle of the segment, ray, or line to delete it. submit
Step1: Subtract 9 from both sides
$$\begin{align*}
-3b+9 - 9&\geq3 - 9\\
-3b&\geq - 6
\end{align*}$$
Step2: Divide both sides by -3 and reverse the inequality sign
When dividing an inequality by a negative number, the inequality sign flips.
$$\begin{align*}
\frac{-3b}{-3}&\leq\frac{-6}{-3}\\
b&\leq2
\end{align*}$$
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The solution of the inequality is \(b\leq2\). On the number - line, we plot a closed circle at \(2\) (because the inequality includes equality, i.e., \(b = 2\) is part of the solution) and draw a ray to the left of \(2\) (since \(b\) can be any number less than or equal to \(2\)).