Question

solve the inequality 3x + 1 ≤ -2 x ≤ ?

Explanation:

Step1: Subtract 1 from both sides

To isolate the term with \( x \), we subtract 1 from both sides of the inequality \( 3x + 1 \leq -2 \). This gives us \( 3x + 1 - 1 \leq -2 - 1 \), which simplifies to \( 3x \leq -3 \).

Step2: Divide both sides by 3

To solve for \( x \), we divide both sides of the inequality \( 3x \leq -3 \) by 3. This gives us \( \frac{3x}{3} \leq \frac{-3}{3} \), which simplifies to \( x \leq -1 \).

Answer:

\( -1 \)