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Question
solve and graph the following inequality: $-7 leq 6x - 9$
inequality:
graph:
Step1: Add 9 to both sides
$$\begin{align*}
-7+9&\leq6x - 9+9\\
2&\leq6x
\end{align*}$$
Step2: Divide both sides by 6
$$\begin{align*}
\frac{2}{6}&\leq\frac{6x}{6}\\
\frac{1}{3}&\leq x
\end{align*}$$
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The inequality is \(x\geq\frac{1}{3}\). To graph it, place a closed - circle at \(\frac{1}{3}\) on the number line (because the inequality is \(\geq\)) and shade to the right of \(\frac{1}{3}\).