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Question
solve the following rational equation.
\\\frac{x}{x + 3} = \frac{8}{x - 2}\\
\\(x = ?, \quad\\)
enter the smallest solution first.
Identify excluded values
$$
x
e -3, \quad x
e 2
$$
Cross-multiply to clear fractions
$$
LATEXBLOCK0
$$
Rearrange into standard quadratic form and solve
$$
LATEXBLOCK1
$$
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Solve the following rational equation.
$$\frac{x}{x + 3} = \frac{8}{x - 2}$$
\(x =\) <blank>-2</blank>, <blank>12</blank>
Enter the smallest solution first.