Question

solve the following quadratic equation.
$x^2 - 1440 = 0$
enter multiple answers separated by a comma or enter none if there are no real solutions.

Explanation:

Step1: Isolate \(x^2\)

Add 1440 to both sides of the equation \(x^2 - 1440 = 0\) to get \(x^2 = 1440\).

Step2: Take square roots

Take the square root of both sides. Remember that \(\sqrt{x^2}=\pm x\), so \(x = \pm\sqrt{1440}\). Simplify \(\sqrt{1440}\): \(1440 = 144\times10\), so \(\sqrt{1440}=\sqrt{144\times10}=12\sqrt{10}\approx 37.95\). Thus, \(x = 12\sqrt{10}, - 12\sqrt{10}\) (or approximately \(37.95, - 37.95\)).

Answer:

\(12\sqrt{10}, -12\sqrt{10}\) (or approximately \(37.95, -37.95\))