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solve the following exponential equation. express the solution set in t…

Question

solve the following exponential equation. express the solution set in terms of natural logarithms or common logarithms. then, use a calculator to obtain a decimal approximation for the solution.
7^{2x} = 889
the solution set expressed in terms of logarithms is \boxed{}.
(use a comma to separate answers as needed. simplify your answer. use integers or fractions for any numbers in the equation. use ln for natural logarithm and log for common logarithm.)

Explanation:

Step1: Take natural log on both sides

To solve the exponential equation \(7^{2x}=889\), we start by taking the natural logarithm (ln) of both sides. This is a common technique for solving exponential equations because it allows us to use the property of logarithms \(\ln(a^b)=b\ln(a)\) to bring down the exponent.

Taking \(\ln\) of both sides gives us:

$$ \ln(7^{2x})=\ln(889) $$

Step2: Apply logarithm power rule

Using the power rule of logarithms \(\ln(a^b) = b\ln(a)\), we can simplify the left - hand side of the equation. For \(a = 7\) and \(b=2x\), we have:

$$ 2x\ln(7)=\ln(889) $$

Step3: Solve for x

Now, we want to isolate \(x\). We can do this by dividing both sides of the equation by \(2\ln(7)\).

$$ x=\frac{\ln(889)}{2\ln(7)} $$

If we want to get a decimal approximation, we can use a calculator to find the values of \(\ln(889)\) and \(\ln(7)\).

We know that \(\ln(889)\approx6.785\) and \(\ln(7)\approx1.9459\)

$$ x=\frac{6.785}{2\times1.9459}=\frac{6.785}{3.8918}\approx1.743 $$

Answer:

In terms of natural logarithms, \(x = \frac{\ln(889)}{2\ln(7)}\); the decimal approximation is \(x\approx1.743\)