Question

solve the following compound inequality.
$-9 \leq 5 + 2x < -5$
$? \leq x < $

Explanation:

Step1: Subtract 5 from all parts

To isolate the term with \(x\), we subtract 5 from each part of the compound inequality.

$$ -9 - 5\leq5 + 2x- 5<-5 - 5 $$

$$ -14\leq2x<-10 $$

Step2: Divide all parts by 2

To solve for \(x\), we divide each part of the inequality by 2.

$$ \frac{-14}{2}\leq\frac{2x}{2}<\frac{-10}{2} $$

$$ -7\leq x<-5 $$

Answer:

\(-7 \leq x < -5\)