Question

1. solve for p in the equation: 4p + 2a - 5 = 6a + p

a. $p = \frac{5 - 4a}{3}$
b. $p = \frac{5 + 4a}{3}$
c. $p = \frac{5 - 4a}{4}$
d. $p = \frac{5 + 4a}{4}$

Explanation:

Step1: Move terms with p to left and others to right

Subtract \( p \) from both sides and add 5 to both sides, also subtract \( 2a \) from both sides:
\( 4p - p = 6a - 2a + 5 \)
Simplify: \( 3p = 4a + 5 \)

Step2: Solve for p

Divide both sides by 3:
\( p = \frac{5 + 4a}{3} \)

Answer:

B. \( p = \frac{5 + 4a}{3} \)