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Question
solve each equation. 2) 3 + r = 2 what is the value of r? r = 1 r = -1 r = 0
Step1: Isolate the variable r.
Subtract 3 from both sides of the equation $3 + r=2$. So, $3 + r-3=2 - 3$.
Step2: Simplify both sides.
On the left - hand side, $3-3 + r=r$, and on the right - hand side, $2-3=-1$. So, $r=-1$.
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$r = - 1$