QUESTION IMAGE
Question
1: solve for x:
25 + 8x = 1
2: solve for x:
\\(\frac{x}{5} + 4 = 6\\)
3: solve for x:
22 = 18x + 4
4: solve for x:
\\(\frac{5 + x}{2} = 4\\)
Problem 1: Solve for \( x \): \( 25 + 8x = 1 \)
Step 1: Subtract 25 from both sides
To isolate the term with \( x \), we subtract 25 from both sides of the equation.
\( 25 + 8x - 25 = 1 - 25 \)
Simplifying both sides, we get:
\( 8x = -24 \)
Step 2: Divide both sides by 8
To solve for \( x \), we divide both sides of the equation by 8.
\( \frac{8x}{8} = \frac{-24}{8} \)
Simplifying both sides, we get:
\( x = -3 \)
Step 1: Subtract 4 from both sides
To isolate the term with \( x \), we subtract 4 from both sides of the equation.
\( \frac{x}{5} + 4 - 4 = 6 - 4 \)
Simplifying both sides, we get:
\( \frac{x}{5} = 2 \)
Step 2: Multiply both sides by 5
To solve for \( x \), we multiply both sides of the equation by 5.
\( 5 \times \frac{x}{5} = 2 \times 5 \)
Simplifying both sides, we get:
\( x = 10 \)
Step 1: Subtract 4 from both sides
To isolate the term with \( x \), we subtract 4 from both sides of the equation.
\( 22 - 4 = 18x + 4 - 4 \)
Simplifying both sides, we get:
\( 18 = 18x \)
Step 2: Divide both sides by 18
To solve for \( x \), we divide both sides of the equation by 18.
\( \frac{18}{18} = \frac{18x}{18} \)
Simplifying both sides, we get:
\( x = 1 \)
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\( x = -3 \)