Question

solve (3+\frac{r}{-4}leq6).
the solution is (square).
graph the solution.

Explanation:

Step1: Isolate the fraction term

Subtract 3 from both sides of the inequality $3+\frac{r}{-4}\leq6$.
$3+\frac{r}{-4}-3\leq6 - 3$
$\frac{r}{-4}\leq3$

Step2: Solve for r

Multiply both sides of the inequality by - 4. When multiplying an inequality by a negative number, the direction of the inequality sign changes.
$\frac{r}{-4}\times(-4)\geq3\times(-4)$
$r\geq - 12$

Answer:

$r\geq - 12$

To graph the solution: On the number - line, there is a closed circle at - 12 (because the inequality includes equality, i.e., $\geq$) and the line extends to the right.