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solve for r. -1(r + 13) ≥ 1

Question

solve for r.
-1(r + 13) ≥ 1

Explanation:

Step1: Distribute -1

$-1\times r+(-1)\times13\geq1$ which simplifies to $-r - 13\geq1$.

Step2: Add 13 to both sides

$-r-13 + 13\geq1+13$, resulting in $-r\geq14$.

Step3: Divide both sides by -1 and reverse the inequality sign

When dividing an inequality by a negative number, the sign flips. So $\frac{-r}{-1}\leq\frac{14}{-1}$, giving $r\leq - 14$.

Answer:

$r\leq - 14$