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2. sketch the graph of (f(x) = \\sin x) for the domain (-360^\\circ \\l…

Question

  1. sketch the graph of (f(x) = \sin x) for the domain (-360^\circ \le x \le 360^\circ). be sure to indicate the values on the (x) and (y) axes of the 5 key points.
  1. based on your graph of (f(x) = \sin x) answer the following questions:

a) what is the amplitude?
b) what is the period?
c) what is the range?
d) what are the (x)-intercepts?

  1. go back to your graph of (f(x) = \sin x) and sketch the graph of a function, (g(x)) that has been horizontally translated (90^\circ) to the right, in the domain (-360^\circ \le x \le 360^\circ). be sure to clearly indicate each function on the graph.

Explanation:

Identify key points of \(f(x) = \sin x\)

Using the Domain and Range knowledge point, we analyze \(f(x) = \sin x\) on \([-360^\circ, 360^\circ]\).
The 5 key points in \([0^\circ, 360^\circ]\) are:

  • \((0^\circ, 0)\)
  • \((90^\circ, 1)\)
  • \((180^\circ, 0)\)
  • \((270^\circ, -1)\)
  • \((360^\circ, 0)\)

Extending to \([-360^\circ, 0^\circ]\):

  • \((-90^\circ, -1)\)
  • \((-180^\circ, 0)\)
  • \((-270^\circ, 1)\)
  • \((-360^\circ, 0)\)

Determine properties of \(f(x) = \sin x\)

From the graph of \(f(x) = \sin x\):

  • Amplitude: The maximum displacement from the midline is \(1\).
  • Period: The length of one complete cycle is \(360^\circ\).
  • Range: The output values lie between \(-1\) and \(1\), written as \([-1, 1]\).
  • x-intercepts: The points where \(f(x) = 0\) are \(-360^\circ, -180^\circ, 0^\circ, 180^\circ, 360^\circ\).

Apply horizontal translation for \(g(x)\)

The function \(g(x)\) is \(f(x)\) translated \(90^\circ\) to the right:

$$g(x) = \sin(x - 90^\circ)$$

We shift each key point of \(f(x)\) by adding \(90^\circ\) to the x-coordinate:

  • \((-360^\circ, 0) \to (-270^\circ, 0)\)
  • \((-270^\circ, 1) \to (-180^\circ, 1)\)
  • \((-180^\circ, 0) \to (-90^\circ, 0)\)
  • \((-90^\circ, -1) \to (0^\circ, -1)\)
  • \((0^\circ, 0) \to (90^\circ, 0)\)
  • \((90^\circ, 1) \to (180^\circ, 1)\)
  • \((180^\circ, 0) \to (270^\circ, 0)\)
  • \((270^\circ, -1) \to (360^\circ, -1)\)
  • \((-360^\circ, -1)\) is obtained by extending the pattern leftward.

Answer:

Question 2

The graph of \(f(x) = \sin x\) is plotted on the domain \([-360^\circ, 360^\circ]\) with key points at:

$$(-360^\circ, 0), (-270^\circ, 1), (-180^\circ, 0), (-90^\circ, -1), (0^\circ, 0), (90^\circ, 1), (180^\circ, 0), (270^\circ, -1), (360^\circ, 0)$$

Question 3

a) What is the amplitude?
<blank>1</blank>

b) What is the period?
<blank>\(360^\circ\)</blank>

c) What is the range?
<blank>\([-1, 1]\)</blank>

d) What are the x-intercepts?
<blank>\(-360^\circ, -180^\circ, 0^\circ, 180^\circ, 360^\circ\)</blank>

Question 4

The graph of \(g(x) = \sin(x - 90^\circ)\) is plotted on the domain \([-360^\circ, 360^\circ]\) with key points at:

$$(-360^\circ, -1), (-270^\circ, 0), (-180^\circ, 1), (-90^\circ, 0), (0^\circ, -1), (90^\circ, 0), (180^\circ, 1), (270^\circ, 0), (360^\circ, -1)$$