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($____$)sin(20°) = 3300; x = \\frac{3300}{sin(\\____ °)}; x ≈ 9648.554;…

Question

($____$)sin(20°) = 3300; x = \frac{3300}{sin(\\____ °)}; x ≈ 9648.554; ski lift, 20°, ground

Explanation:

Step1: Analyze the first equation

We have \((\underline{})\sin(20^{\circ}) = 3300\). Let the unknown be \(x\), so \(x\sin(20^{\circ})=3300\). To solve for \(x\), we divide both sides by \(\sin(20^{\circ})\), so \(x=\frac{3300}{\sin(20^{\circ})}\).

Step2: Identify the angle in the sine function

From the first equation, the angle in the sine function is \(20^{\circ}\), so the blank in the denominator of the second equation should be \(20\).

Answer:

For the first blank (the coefficient of \(\sin(20^{\circ})\)): \(x\) (or the variable representing the hypotenuse, which is \(x\) here)
For the second blank (the angle in \(\sin(\underline{}^{\circ})\)): \(20\)