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Question
simplify. rewrite the expression in the form $4^n$. $\frac{4^{11}}{4^{-8}} = \square$
Step1: Apply exponent division rule
For same bases, $\frac{x^a}{x^b}=x^{a-b}$
$\frac{4^{11}}{4^{-8}}=4^{11-(-8)}$
Step2: Simplify the exponent
Calculate the subtraction of exponents
$4^{11+8}=4^{19}$
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$4^{19}$