Question

simplify. express your answer using positive exponents.
\\(\frac{8f^{-4}g^{-7}}{f^{-8}g^{-8}}\\)

Explanation:

Step1: Use quotient - rule of exponents

When dividing like - bases \(a^m\div a^n=a^{m - n}\), we have \(\frac{8f^{-4}g^{-7}}{f^{-8}g^{-8}}=8\times f^{-4-(-8)}\times g^{-7-(-8)}\).

Step2: Simplify the exponents

\(-4-(-8)=-4 + 8 = 4\) and \(-7-(-8)=-7 + 8 = 1\). So the expression becomes \(8f^{4}g^{1}\).

Answer:

\(8f^{4}g\)