Question

simplify. express your answer as a single term, without a denominator.
$c^2 \cdot c^0$

Explanation:

Step1: Recall exponent rule

When multiplying exponents with the same base, we use the rule \(a^m \cdot a^n = a^{m + n}\). Also, any non - zero number to the power of 0 is 1, so \(c^0=1\) (assuming \(c
eq0\)).

Step2: Apply the rules

For the expression \(c^{2}\cdot c^{0}\), first, since \(c^0 = 1\), we can also use the exponent addition rule. Here, \(m = 2\) and \(n=0\), so \(c^{2}\cdot c^{0}=c^{2 + 0}\).

Step3: Simplify the exponent

\(c^{2+0}=c^{2}\).

Answer:

\(c^{2}\)