QUESTION IMAGE
Question
simplify.
e^{\ln x} =
e^{\ln 5} =
e^{\ln 3x}
Step1: Apply logarithm-exponent identity
Recall the identity $e^{\ln a} = a$ (since $e$ and $\ln$ are inverse functions).
For $e^{\ln x}$:
$e^{\ln x} = x$
Step2: Apply identity to second term
For $e^{\ln 5}$:
$e^{\ln 5} = 5$
Step3: Apply identity to third term
For $e^{\ln 3x}$:
$e^{\ln 3x} = 3x$
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$e^{\ln x} = x$
$e^{\ln 5} = 5$
$e^{\ln 3x} = 3x$