Question

simplify.

\\((-i)^{88}\\)

\\((-i)^{88} = \\)

(simplify your answer. type your answer in the form \\(a + bi\\).)

Explanation:

Separate the base factors

$$ (-i)^{88} = (-1 \cdot i)^{88} = (-1)^{88} \cdot i^{88} $$

Evaluate the real base power

$$ (-1)^{88} = 1 $$

Evaluate the imaginary base power

$$ i^{88} = (i^4)^{22} = 1^{22} = 1 $$

$$ (-i)^{88} = 1 \cdot 1 = 1 = 1 + 0i $$

Answer:

Simplify.

$$(-i)^{88} =$$

<blank>\(1 + 0i\)</blank>
(Simplify your answer. Type your answer in the form \(a + bi\).)