Question

simplify.
-5·10i
write your answer in the form a + bi.
save answer

Explanation:

Step1: Multiply the real numbers

To simplify \(-5 \cdot 10i\), we first multiply the coefficients \(-5\) and \(10\).
\(-5\times10=-50\)
So, \(-5 \cdot 10i=-50i\)

Step2: Write in \(a + bi\) form

In the form \(a+bi\), \(a\) is the real part and \(b\) is the coefficient of the imaginary part. Here, the real part \(a = 0\) and the coefficient of \(i\) (the imaginary part) \(b=- 50\). So we can write it as \(0-50i\) or simply \(0 + (-50)i\) which is \(0-50i\) (or \(0 + (-50)i\)). But usually, we write it as \(0-50i\) or just \(-50i\) (since \(0\) as the real part can be omitted in the sense that \(0+(-50)i=-50i\)). But to strictly follow \(a + bi\) form with \(a\) and \(b\) shown, we have \(a = 0\) and \(b=-50\), so \(0+(-50)i\) or \(0 - 50i\).

Answer:

\(0 - 50i\) (or equivalently \(0+(-50)i\))