QUESTION IMAGE
Question
- simplify: (-2v^9) cdot (-4v^2)
Step1: Multiply the coefficients
$(-2)\times(-4)=8$
Step2: Use the product - rule of exponents
When multiplying two terms with the same base $v$, we add the exponents. So $v^{9}\times v^{2}=v^{9 + 2}=v^{11}$
Step3: Combine the results
The product of $(-2v^{9})$ and $(-4v^{2})$ is $8v^{11}$
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$8v^{11}$