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show that the measure of an exterior angle is always equal to the sum o…

Question

show that the measure of an exterior angle is always equal to the sum of the measures of its non - adjacent interior angles. use the figure below to help.
first identify the types of angles in the figure.
the exterior angle is ∠4. the non - adjacent interior angles are ∠1 and ∠3
non - adjacent angles are on the opposite side of the triangle from the exterior angle

Explanation:

Step1: Use angle - sum property of a triangle

In a triangle, the sum of interior angles is \(180^{\circ}\). So, \(\angle1+\angle3+\angle5 = 180^{\circ}\), where \(\angle5\) is the interior angle adjacent to \(\angle2\) (since \(\angle2\) and \(\angle5\) form a linear pair). Then \(\angle5=180^{\circ}-\angle2\). Substituting \(\angle5 = 180^{\circ}-\angle2\) into \(\angle1+\angle3+\angle5 = 180^{\circ}\), we get \(\angle1+\angle3+(180^{\circ}-\angle2)=180^{\circ}\).

Step2: Simplify the equation

Subtract \(180^{\circ}\) from both sides of the equation \(\angle1+\angle3+(180^{\circ}-\angle2)=180^{\circ}\). We have \(\angle1+\angle3-\angle2=0\). Then, by adding \(\angle2\) to both sides, we get \(\angle2=\angle1 + \angle3\).

Answer:

The measure of an exterior angle (\(\angle2\)) of a triangle is equal to the sum of the measures of its non - adjacent interior angles (\(\angle1\) and \(\angle3\)) as shown by using the angle - sum property of a triangle (\(\angle1+\angle3+\angle5 = 180^{\circ}\)) and the linear - pair property (\(\angle2+\angle5 = 180^{\circ}\)).