Question

1. shea wrote the expression 5(y + 2) + 4 to show the amount of money five friends paid for snacks at a baseball game. which expression is equivalent to the one shea wrote?

a. 5 + y + 5 + 2 + 4
b. 5 · y + 5 · 2 + 4
c. 5 · y · 5 · 2 + 4
d. 5 · y · 4 + 5 · 2 · 4

1. evaluate the expression below.

$6^2 - 3(-4)$

1. what is the value of the expression below?

$6 + 5(9 ÷ 3)^2$

a. 36
b. 51
c. 99
d. 11

is the value of the expression below?
$3^5 ÷ 3^3 = $

1. mr. gonzales showed students part of the prime factorization of 90. one factor is missing.

$2 · 3^2 · $ __

Explanation:

Problem 4

Step1: Apply distributive property

$5(y+2)+4 = 5\cdot y + 5\cdot2 + 4$

Step2: Match with options

Compare to given choices.

Problem 5

Step1: Calculate exponent

$6^2 = 36$

Step2: Multiply the terms

$3(-4) = -12$

Step3: Subtract the values

$36 - (-12) = 36 + 12 = 48$

Problem 6

Step1: Solve inside parentheses

$9\div3 = 3$

Step2: Calculate exponent

$3^2 = 9$

Step3: Multiply then add

$5\cdot9 = 45; 6 + 45 = 51$

Problem 7 (incomplete, assuming $3^5$)

Step1: Expand the exponent

$3^5 = 3\times3\times3\times3\times3 = 243$

Problem 8

Step1: Prime factorize 90

$90 = 2\times3^2\times5$

Step2: Identify missing factor

Find the unlisted prime factor.

Answer:

1. b. $5 \cdot y + 5 \cdot 2 + 4$
2. $48$
3. b. 51
4. $243$ (assuming the expression is $3^5$)
5. $5$