Question

shani poses as the statue of liberty for an art class. she holds a torch above her head with her right hand and a book against her side with her left hand. she holds the pose for ten minutes. at the end of the session, she mentions to her friend that it was a lot of work to pose and that her arms are really tired. which describes the work shani did while she posed?(assume the starting work position is when her hand is already raised ) she did more work with her right hand than with her left because the right was held up higher. she did no work while she posed because she did not move the torch or the book. she did work while she posed because she was tired at the end of the session. she did no work while she posed because she did not exert a force on anything.

Explanation:

Step1: Recall work - physics definition

Work is defined as the product of force and displacement in the direction of the force, $W = F\times d$.

Step2: Analyze Shani's situation

When Shani is posing and holding the torch and book in place, there is no displacement of the torch or book in the direction of the force she is exerting on them (to hold them up). Since $d = 0$, then $W=F\times0 = 0$. Just being tired is due to the internal muscle - work in the body which is not the same as the work done on the external objects (torch and book) in the physics sense.

Answer:

She did no work while she posed because she did not move the torch or the book.