Question

a sequence is defined recursively using the equation $f(n + 1) = f(n) - 8$. if $f(1) = 100$, what is $f(6)$?
\bigcirc\\ 52
\bigcirc\\ 60
\bigcirc\\ 68
\bigcirc\\ 92

Explanation:

Step1: Find f(2)

Given \( f(n + 1)=f(n)-8 \) and \( f(1) = 100 \). For \( n = 1 \), \( f(2)=f(1)-8=100 - 8=92 \)

Step2: Find f(3)

For \( n = 2 \), \( f(3)=f(2)-8=92 - 8 = 84 \)

Step3: Find f(4)

For \( n = 3 \), \( f(4)=f(3)-8=84 - 8=76 \)

Step4: Find f(5)

For \( n = 4 \), \( f(5)=f(4)-8=76 - 8 = 68 \)

Step5: Find f(6)

For \( n = 5 \), \( f(6)=f(5)-8=68 - 8=60 \)

Answer:

60